Math, asked by Rohit12102007, 3 months ago

Find the smallest number or smallest expression by which
the following numbers should be multiplied so that the
product is a perfect cube.

answer the questions which I marked

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Answers

Answered by pranayasahu
0

Step-by-step explanation:

Prime factorising 7803, we get,

7803=3×3×3×17×17

=3

3

×17

2

.

We know, a perfect cube has multiples of 3 as powers of prime factors.

Here, number of 3's is 3 and number of 17's is 2.

So we need to multiply another 17 to the factorization to make 7803 a perfect cube.

Hence, the smallest number by which 7803 must be multiplied to obtain a perfect cube is 17.

Answered by riyasingh7376700201
2

Answer:

here is your solution of your question

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