Find the smallest number or smallest expression by which
the following numbers should be multiplied so that the
product is a perfect cube.
answer the questions which I marked
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Step-by-step explanation:
Prime factorising 7803, we get,
7803=3×3×3×17×17
=3
3
×17
2
.
We know, a perfect cube has multiples of 3 as powers of prime factors.
Here, number of 3's is 3 and number of 17's is 2.
So we need to multiply another 17 to the factorization to make 7803 a perfect cube.
Hence, the smallest number by which 7803 must be multiplied to obtain a perfect cube is 17.
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