find the smallest number that become a perfect cube when devided by 3 and a perfect.square when devided by 2
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128÷2=64=23×23=43 128 ÷ 2 = 64 = 2 3 × 2 3 = 4 3 is a perfect cube. Hence the smallest number by which 128 should be divided to make a perfect cube is 2 . Here, the prime factors 5 is not present as triples. Hence, we divide 135 by 5, so that the obtained number becomes a perfect cube
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