Math, asked by Sveta, 1 year ago

find the smallest number that can be divided by 254 and 508 which leaves remainder 4?
508
516
512
520
please explain step by step

Answers

Answered by neha2361
0

Answer:

512 is smallest number ,can be divided by 254 and 508 which leaves remainder 4

Answered by sk940178
1

The required number is 512

Step-by-step explanation:

The smallest number that can be divided by 254 and 508 will be the least common multiple of 254 and 508.

Now, we have 254 × 2 = 508.

Hence, 508 is the least common multiple of 254 and 508.

Now, dividing 508 by 254 and 508 will leave the same remainder 4 in both cases.  

Therefore, the required number is (508 + 4) = 512 (Answer)

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