find the smallest number that can be divided by 254 and 508 which leaves remainder 4?
508
516
512
520
please explain step by step
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Answered by
0
Answer:
512 is smallest number ,can be divided by 254 and 508 which leaves remainder 4
Answered by
1
The required number is 512
Step-by-step explanation:
The smallest number that can be divided by 254 and 508 will be the least common multiple of 254 and 508.
Now, we have 254 × 2 = 508.
Hence, 508 is the least common multiple of 254 and 508.
Now, dividing 508 by 254 and 508 will leave the same remainder 4 in both cases.
Therefore, the required number is (508 + 4) = 512 (Answer)
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