Math, asked by Anonymous, 7 months ago

Find the smallest number that divides 13 and 8 leaving remainder 1 and 2 respectively.
Please solve it.

I need Step by Step explanation.

Answer → 3​

Answers

Answered by Anonymous
10

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Remainders are = 1 and 2

divisors are = 13 and 8

Let dividers are x

13-1=12 and 8-2=6

now we have find that number that Easily Divides 12 and 6 i.e 2 and 3 but 3 will be the answer Beacuse when 13 is divide by 2 n 3 Remainder will be 1 and 1 , when 8 is divide by 2 n 3 Remainders will be 0 and 2.

Answer is 3

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