Question

find the smallest number that divides 15 25 and 35 and leaves remainder 5 in each case​

Answer 1

Answer:

Let m be the number

Then m-5 will be the lcm of 15, 25 and 35

15=3x5

25=5x5

35=5x7

So lcm =3x5x5x7 = 525

So the smallest number which when divided by 15, 25 and 35 leaves a remainder 5 is 530

Answer 2

Answer:  10

Explanation: 10 x 1 is 10 which is 5 less than 15.

                      10 x 2 is 20 which is 5 less than25.

                      10 x 3 is 30 which is 5 less than 35.