Math, asked by vive1234, 6 months ago

Find The smallest number that divides by 44,55 and 220 leaving remainder 5.​

Answers

Answered by BeStMaGiCiAn14
0

First of all ,  We will find the L.C.M of 44, 55 and 220.  

It would come to 220. Now according to the question ,  when 90 would be divided by 44, 55 & 220, it should leave a remainder 5.  

Therefore we add 5 to 220 = 225  Cross check:-  

a) 225/44 has a Remainder = 5

b) 225/55 has a Remainder = 5

c) 225/220 has a Remainder =5  Thus the answer is 225.

Answered by Anonymous
1

Answer:

We have to find LCM of 44,55,220 which is 220

To leave the reminder as 5, we have to add 5 to the LCM

Therefore. 225 is the smallest number that divides by 44, 55 and 220 leaving remainder 5

Step-by-step explanation:

LCM(44,55,220)+5

=)220+5

=)225

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