Math, asked by diwaker971, 3 months ago

Find the smallest number that divides by 44,55 and 220 leaving remainder 5

Answers

Answered by Archita88

2

Answer:

LCM (44,55,220) by prime factorisation method

44 = 2x2x11

55 = 5x11

220 = 2x2x5x11

LCM(44,55,220) = 2x2x5x11 = 220

220 + 5 = 225

If we devided 225 by 44,55,220 it will leave remainder as 5.

Step-by-step explanation:

I hope this helps you

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