Math, asked by nidatthtecelu, 1 year ago

Find the smallest number that divides by 44,55 and 220 leaving remainder 5.

Answers

Answered by Manjula29
102
First of all ,  We will find the L.C.M of 44, 55 and 220.  It would come to 220. Now according to the question ,  when 90 would be divided by 44, 55 & 220, it should leave a remainder 5.  Therefore we add 5 to 220 = 225  Cross check:-  a) 225/44 has a Remainder = 5  b) 225/55 has a Remainder = 5  c) 225/220 has a Remainder =5  Thus the answer is 225.
Answered by sangeetakumari990506
14

Answer:

Step-by-step explanation:

First of all ,  We will find the L.C.M of 44, 55 and 220.  It would come to 220. Now according to the question ,  when 90 would be divided by 44, 55 & 220, it should leave a remainder 5.  Therefore we add 5 to 220 = 225  Cross check:-  a) 225/44 has a Remainder = 5  b) 225/55 has a Remainder = 5  c) 225/220 has a Remainder =5  Thus the answer is 225.

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