Question

find the smallest number that divisible by44,55,and220 leaving the remainder 5​

Answer 1

Answer:

Yes! Here is your answer!

Step-by-step explanation:

First of all ,  We will find the L.C.M of 44, 55 and 220.

It would come to 220. Now according to the question ,  when 90 would be divided by 44, 55 & 220, it should leave a remainder 5.

Therefore we add 5 to 220 = 225  Cross check:-

a) 225/44 has a Remainder = 5

b) 225/55 has a Remainder = 5

c) 225/220 has a Remainder =5  Thus the answer is 225.