Find the smallest number that is by 144,160 mcl gu Without leaving remainder
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Answer:
Smallest that perfectly divide these two numbers = 16.
Step-by-step explanation:
144 = 12 × 12 = 2 × 2 × 2 × 2 × 3 × 3 = 16 × 9
160 = 8 × 2 × 2 × 5 = 16 × 10
HCF = 16
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