Question

Find the smallest number that is by 144,160 mcl gu Without leaving remainder

Answer 1

Answer:

Smallest that perfectly divide these two numbers = 16.

Step-by-step explanation:

144 = 12 × 12 = 2 × 2 × 2 × 2 × 3 × 3 = 16 × 9

160 = 8 × 2 × 2 × 5 = 16 × 10

HCF = 16