Math, asked by 9691797430rajeshkurm, 7 months ago

Find the smallest number that is divisible by 20,25
and 30.​

Answers

Answered by varunchandar05
0

Answer:

300

Step-by-step explanation:

lcm of 20,25 and 30 is the answer

20=2^2*5

25=5^2

30=2*3*5

lcm=2^2*5^2*3

=300

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Answered by ghatejanhavi74
2

10200

Step-by-step explanation:

So, we will multiply the L.C.M. by a number that makes it the least five digit number divisible by 20, 25, 30. So, the least five digit number divisible by 20, 25, 30 is 10200.

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