Math, asked by pathakgopal733, 9 months ago

find the smallest number that is divisible by 27 and 36.​

Answers

Answered by riya5395
1

Answer:

The smallest number that can divide 40, 50, 75, and 90.

List all factors of each. 40 = 1, 2, 5, 8, 20, 40

50 = 1, 2, 5, 10, 25, 50

75 = 1, 3, 5, 15, 25, 75

90 = 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

The smallest number that can divide into 40, 50, 75 and 90 is 5.

Smallest number divisible by 36, 18, 27.

List multiples of each: 36 = 36, 72, 108, 144, ...

18 = 18, 36, 54, 72, 90, 108, ...

27 = 27, 54, 81, 108

Smallest number divisible by 36, 18, 27 is 108.

Smallest number divisible by 30, 40, and 50

Prme factorization of each: 30 = 2*3*5

40 = 2^3*5

50 = 2*5^2

Smallest number divisble by 30, 40, and 50 would be 2^3*3*5^2 or 600.

Answered by vatsalaagarwal1508
6

Answer:

here is your answer mate

l.c.m. is 108

solution is given above in the pic

Hope it helps please mark it as the brainliest answer ☺️ please please

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