Question

find the smallest number that is divisible by 35,45 and55, leaving remainder17 ,27 and 37 respectively

Answer 1

LCM of 35 45 55 is 3465

so for 1st number 35 answer is 3465+17= 3482

2nd number answer is 3465+27 = 3492

3rd number answer is 3465+37 = 3502

I hope it will help you.

Answer 2

Answer:

The smallest number is 3447

Step-by-step explanation:

To find the smallest number,

We have to find out the LCM of 35, 45, and 55

LCM of 35, 45, and 55 = 3465

Find out the difference of the the number and the reminder

18 is the difference of (35-17) = (45-27) = (55-37) = 18

Hence, smallest number which is divisible by the given number is = 3465 - 18 = 3447