Question

find the smallest number that leaves 5 as remainder when divided by 36 and 54

Answer 1

n = 5 + LCM(36,54)
n = 5 + LCM(9*2*2, 9*3*2)
n = 5 + 9*2*2*3 = 113

Answer 2

\displaystyle\text{LCM of 36,54}\\Factors = 2 \times 2 \times 3 \times 3 \times 3\\LCM = 108\\\\\text{We need to find smallest number leaving remainder 5}\\So, 108 + 5 = 113\\\\\therefore \text{The number is} \boxed{\boxed{113}}