find the smallest number that leaves 5 as remainder when divided by 36 and 54
Answers
Answered by
8
Answer: ANSWER = 113
Step-by-step explanation:
the smallest such number will be the (LCM of 36 and 54) + 5
LCM of 36 and 54 = 108
the number will be 108+ 5 = 113
ANSWER = 113
CHEERS MATE, PLEASE MARK BRAINLIEST
Answered by
3
Smallest number that leaves 5 as remainder when divided by 36 and 54
= 108+5= 113
Attachments:
Similar questions