Question

find the smallest number that leaves 5 as remainder when divided by 36 and 54​

Answer 1

Step-by-step explanation:

firstly find the LCM of 36 and 54

L.C.M.(36,54)=108

Remainder = 5

Smallest number that leaves remainder 5 with 36 and 54 both=108+5

=113

Answer 2

Answer:

113

Step-by-step explanation:

take LCM of 36 and 54

the LCM is 108

adding the remainder 5 with LCM

=108+5=113

so,113 is the smallest no. which leaves remainder 5 when divided by 36 and 54.