Question

Find the smallest number that leaves 5 as remainder when devided by 36 and 56.​

Answer 1

Answer:

113

Step-by-step explanation:

Find LCM of 54 and 36

54 = 2×3×3×3

36 = 2×2×3×3

LCM = 2×2×3×3×3 = 108

So when you divide 108 by 36 or 54, remainder will be zero.

You want remainder to be 5. So add 5 to 108. You will get 113.

When you divide 113 by 36 or 54, remainder will be 5.

113 is your answer