Question

find the smallest number that leaves 5 as remainder when divided by 36 and 54

Answer 1

Let the number be 'x'
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So, when divided by 36,the number is x
and remainder is 5
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A/Q
$\frac{x}{36} = 5 \\ = > x = 180$

So,the smallest number which when divided by 36 leaves remainder 5 is 180,
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Similarly,
$\frac{x}{54} = 5 \\ = > x = 270$
So,the smallest number which when divided by 54 leaves remainder 5 is 270.
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Answer 2

Find LCM of 54 and 36

54 = 2×3×3×3
36 = 2×2×3×3

LCM = 2×2×3×3×3 = 108

So when you divide 108 by 36 or 54, remainder will be zero.

You want remainder to be 5. So add 5 to 108. You will get 113.

When you divide 113 by 36 or 54, remainder will be 5.

113 is your answer