Question

Find The Smallest Number That Leaves 5As Remainder When Divide By36 And 54

Answer 1

Answer:

113

Reason:

The smallest no. that leaves 5 as remainder when divided by 36 and 54 is LCM of 36and 54plus(+)5;

LCM of 36 and 54

By prime factorisation,

36=2×3×3×2×1

54=2×3×3×3×1

LCM=2×3×3×3×2=108.

Now the smallest no. which leaves 5 as remainder is 108+5=113.