Question

Find the smallest number that leaves a remainder of 4 on division by 5, 5 on division by 6, 6 on division by 7, 7 on division by 8 and 8 on division by 9?
2519
5039
1079
979

Answer 1

Answer:

Step-by-step explanation:

We have to take lcm of them and substract one from it

Lcm=(5,6,7,8,9)-1

=2519

Answer 2

The correct option is A) 2519.

Step-by-step explanation:

Consider the provided information.

First find the LCM of 5, 6, 7, 8 and 9

The LCM of 5, 6, 7, 8 and 9 is 2520

That means the least number which is divisible by 5, 6, 7, 8 and 9 is 2520.

Now the subtract the difference of remainder and divisor.

6-5=1

7-6=1

8-7=1

9-8=1

Therefore, subtract 1 from the obtained LCM.

2520-1=2519

Hence, the correct option is A) 2519.

#Learn more

What least number should be added to 3756 so that the sum can be exactly divided by 45 ?

brainly.in/question/3761379