Question

Find the smallest number that must be added to 1568,so that it becomes exactly divisible by 5
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Answer 1

Answer:

$\huge\red{Method-1}$ :-

'2' is the smallest number that must be added to 1568 to divisible by 5 .

• 1568 + 2
• $\sf\green{1570}$

$\huge\red{Method-2}$ :-

Prime factorisation of "1568"

• 2*2*2*2*2*7*7

Prime factor is $\tt\pink{2}$

Hence, 2 is the smallest number.