Question

find the smallest number that must be subtracted from 682 to make it a perfect cube

Answer 1

Solution:-
Perfect square near 682 is 8
which is,8×8×8=512
9cube=9×9×9=729

Let the number be subtracted from 682 be x.

682-x=512
x=170

So,the number which must be subtracted from 682 to make is perfect cube is 170.

Answer 2

Answer:

the number which must be subtracted from $682$ to make it a perfect cube is $170$.

Step-by-step explanation:

From the question,

We need to find the smallest number that must be subtracted from $682$ to make it a perfect cube.

Then,

First, we need to find the nearest perfect cube of $682$.

The perfect cube near $682$ is $512$ and $729$.

which is,

$8X8X8=512\\\\9X9X9=729$

$729$is bigger than $682$, So from it, we can't subtract.

Let the number be subtracted from $682$ be $x$.

$682-x=512\\\\x=170$

Hence, the number which must be subtracted from $682$ to make it a perfect cube is $170$.