Math, asked by Venomchuckle, 5 months ago

Find the smallest number that on division by 16 and 48 leaves 2 as remainder in each case.

Answers

Answered by epshitaepshita830

0

Answer:

16 ÷ 50 = 3

2 as a remainder, 3 as a quotient and 50 as a divident

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