Find the smallest number that should be added to 2000, so that the sum is exactly divisible by 10,20,30.
Answers
Answered by
5
The smallest number that must be added to 2000 to make it divisible by 10, 20 and 30 is 40.
Verification:
2000 + 40 = 2040.
1) 2040 ÷ 10 = 204.
2) 2040 ÷ 20 = 102.
3) 2040 ÷ 30 = 68.
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Answered by
8
the number exactly divisible by 10,20,30 are 60 (LCM)
or multiples of 60
now divide 2000 by 60
we get
2000 =33×60 +20
so 40 must be added to be divisible 60 that is divisible by 10,20,30
now u get 2040 =2000 +40
or multiples of 60
now divide 2000 by 60
we get
2000 =33×60 +20
so 40 must be added to be divisible 60 that is divisible by 10,20,30
now u get 2040 =2000 +40
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