Question

find the smallest number that should be added to (a) 4013 to make it divisible by 3 (b) 56327 to make it divisible by9​

Answer 1

Answer:

a) 1

b) 1

Step-by-step explanation:

a) 4013+1=4014 which is divisible by 3

b) 56327+1=56328 which is divisible by 9

Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

For divisible by 3 the sum of digits must be divisible by 3 or a multiple of 3.

Now, a) 4013 =>4+0+1+3=8

The sum of digits of 4013 is 8 we know that 9 is divisible by 3 so,to make it divisible we add 1 to it to make it divisible by 3.

Answer is 1

1 is the smallest number that should be added to 4013 to make it divisible by 3.

4014÷3=1338

(b)

For the number divisible by 9 the sum of digits of number must be divisible by 9.

56327=>5+6+3+2+7=23

We obtained 23 as 23 is not divisible by 9.So,to make it divisible by 9 add 4.

Answer is 4

4 is the smallest number that should be added to 56327 to make it divisible by 9.

56331 ÷ 9=6259