Question

Find the smallest number that when divided by 20,45 and 85 leaves a remainder 7in each case​

Answer 1

Answer:

3067

Step-by-step explanation:

Find the LCM of 20, 45 and 85

20 = 2x2x5

45 = 3x3x5

85 = 5x17

The LCM is 2x2x3x3x5x17 = 3060

Next add 7 to 3060 to get 3067 as the answer.

Check: 3067 divided by 20 = 153 as quotient and a remainder of 7. Correct.

3067 divided by 45 = 68 as quotient and a remainder of 7. Correct.

3067 divided by 85 = 36 as quotient and a remainder of 7. Correct.

3067 is the answer.