Question

Find the smallest number that when divided by 35, 56 and 91 leaves remainders of 7 in each case?

Answer 1

Answer:

factors of

35 = 5 × 7

56 = 2 × 2 × 2 × 7

91 = 7 × 13

lcm of 35,56,91 will be

5 × 7 × 2 × 2 × 2 × 13 = 3640

so the no which leaves remainder of 7

3640+7 = 3647

cross check

3647/35 = 104(quotient) & 7(remainder)

3647/56 = 65 ("") & 7 ("")

3647/91 = 40 ("") & 7 ("")