Question

find the smallest number that when divided by 35, 56 and 91 leaves remainder of 7 in each case

Answer 1

LCM equal to 7 x 5 x 2 x 2 x 2 x 13 = 3640
smallest no. 3640
condition 7 remainder
so we add
3640 + 7 = 3647

Answer 2

first find the lcm of 35,56,91
then add 7 to the lcm obtained.
then the answer will be 3647