Question

Find the smallest number that when divided by 3556 and 91 leaves the remainder of 7 in each case

Answer 1

1] What is the smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case?                     2] Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21.                                                                                                                                               3] A circular field has a circumfrence of 360 km. Three cyclists start together and can cycle 48 km, 60 km and 72 km a day, round the field. When will they meet again?

Answer 2

The answer is 21.

Firstly minus 7 from both the numbers.

You will get 3549 and 84.

Now find HCF of these two numbers using lon division method.

You will get the answer 21.