Question

Find the smallest number to be added or subtracted so that 11715 is divisible by 6 and 9

Answer 1

Answer:

3 is the smallest number to be added to 11715 such that it is divisible by both 6 and 9

Step-by-step explanation:

First we will check divisibility rule with 9

1+1+7+1+5= 15 which isn't divisible by 9

next number which is divisible by 9= 18

18-15= 3

11715+3= 11718

1+1+1+7+1+8= 18 which is divisible by 9

Now we will check with 6 by using divisibility rule

11718 is an even number so it is divisible 2

1+1+1+7+1+8= 18 which is divisible by 3

Hence, divisible 6

11718 is divisible by both 6 and 9