Question

find the smallest number w which divided by 25, 42 and 60 leaves remainder 7 in each case​

Answer 1

Answer:

2107

Step-by-step explanation:

Given,

3 numbers = 25, 42 and 60

lcm of 25,42,60:

LCM(25,42) = (25 × 42) / GCF(25,42)

= (25 × 42) / 1

= 1050 / 1

= 1050

LCM(1050,60) = (1050 × 60) / GCF(1050,60)

= (1050 × 60) / 30

= 63000 / 30

= 2100

Therefore,  LCM(25, 42, 60) = 2100

Given, it leaves a remainder of 7

So the number is 2100+7=2107.

therefore 2107 is the smallest no. which when divided by 25,50 and 60 leaves a remainder of 7.

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