Find the smallest number when divided by 28 , 32,48, 72 leaves 5 as reminder
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Step-by-step explanation:
find the l.c.m of 28,32,48 and 72
28=2^2×7
32=2^5
48=2^4×3
72=2^3×3^2
hence l.c.m= 2^5×3^2×7=2016
28,32,48,72 leaves a remainder of 5
so 2016+5= 2021 is the answer
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