Math, asked by kuttappayi7966, 1 year ago

Find the smallest number when divided by 28 , 32,48, 72 leaves 5 as reminder

Answers

Answered by ericksimba100
0

Answer:

Step-by-step explanation:

find the l.c.m of 28,32,48 and 72

28=2^2×7

32=2^5

48=2^4×3

72=2^3×3^2

hence l.c.m= 2^5×3^2×7=2016

28,32,48,72 leaves a remainder of 5

so 2016+5= 2021 is the answer

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