Question

Find the smallest number when divided by 28,40,and 44 leave a remainder 8 in each case​

Answer 1

$Find \:the \:LCM \: of \: 28,40 \:and \: 44$

2 | 28,40,44

___________

2 | 14 , 20, 22

___________

*** 7 , 10 , 11

LCM of 28,40 and 44

= 2×2×7×10×11

= 3080

$\red{Least \: number \: which \:when \: divided \:by}$

$\red{28,40\:and \: 44 \: leaves \: the \: same}$

$\red{ remainder \: 8 \: in \: each \:case}$

$= LCM(28,40,44) + 8$

$= 3080 + 8$

$\green { = 3080}$

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Answer 2

Step-by-step explanation:

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