Question

find the smallest number when divided by
28 and 32 leaves remainder 8 and 12 respectively.

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Answer 1

Answer:

ATQ,

x/28=8

x=28×8

x=224

and,

x/32=12

x=12×32

x=185

so ,ans. are 224 and 185 respectively

Answer 2

28-8=20
32-12=20
HCF (20,20)=20