Find the smallest number when divided by 40,60 and 100 leaves 24 as remainder in each case
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L.C.M of 40,60,100.
factors=2 * 2 * 2 * 3 * 3 * 5 * 5
L.C.M= 1800
smallest number by leaving remainder 24 in each case:
⇒1800+24
⇒1824.
factors=2 * 2 * 2 * 3 * 3 * 5 * 5
L.C.M= 1800
smallest number by leaving remainder 24 in each case:
⇒1800+24
⇒1824.
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