find the smallest number when increased by 19 will be exactly divisible by 24,78,96and 144
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The given numbers are 520 and 468.
The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is obtained by subtracting 17 from the LCM of 520 and 468.
520=2×2×2×5×13
468=2×2×3×3×13
LCM of 520 and 468 = 2×2×2×3×3×5×13=4680
Smallest number which when increased by 17 is exactly divisible by both 520 and 468=4680−17
=4663
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