Find the smallest number which can divided by 30 and 70 leave a reminder 12 in each case
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Answer:
30-12=18
70-12=58
now to find the smallest number which is divisible by 30 and 70 by leaving a remainder 12,we need to find the LCM of 18 and 58
LCM of 18 and 58 is
Step-by-step explanation:
18:58
2!9:29
LCM of 18 and 58 is 2×9×29=522
therefore required smallest number is 522
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