Question

find the smallest number which devides by 20 25 50 leaving remainder 9​

Answer 1

Smallest number which is divisible by 20, 25 and 50 will be their LCM which is 100.

So the smallest number which divides by 20 25 50 leaving remainder 9​ will be 100 + 9 = 109

Answer 2

Step-by-step explanation:

Smallest number which divides 20, 25, 50 is L.C.M. of them which is 100

and the number will be 100+9 = 109