Question

find the smallest number which divided by 8,9,10,15,20 gives a remainder of 3 everytime.​

Answer 1

Answer:

Hence, 365 is the smallest number which when divided by 8, 9, 10, 15, 20 gives a remainder of 5 every time.

Step-by-step explanation:

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Answer 2

2÷4=8

3÷3=9

2÷5=10

3÷5=15

2÷10=20