Find the smallest number which divides by 12 15 and 21 leaves a remainder 7 in each case
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Step-by-step explanation:
Prime factorization first.
12 = 2 x 2 x 3
15 = 3 x 5
21 = 3 x 7
LCM = 2 x 2 x 3 x 5 x 7 = 420
Since all of the number leaves a remainder 7.
∴ The number will be 420 + 7 = 427
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