Question

find the smallest number which increased by 17 is exactly divisible by 250 and 468

Answer 1

LCM of 520 and 468 = 2 × 2 × 2 × 3 × 3 × 5 × 13 = 4680. Smallest number which when increased by 17 is exactly divisible by both 520 and 468 = 4680 17 = 4663. The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is obtained by subtracting 17 from the LCM of 520 and 468