Find the smallest number which is completely divisible by 11, And those number divided by 3 , 4 , 6 and 9 remainder comes 2.
please , give appropriate answer with some explanation .
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Take the LCM of 3, 4, 6 & 9
LCM = 2 * 2 * 3 * 3 = 36
i.e. 36 can divide 3,4,6,9 completely.
and 38 can divide 3, 4, 6, 9 leaving remainder 2.
Multiples of 36 = 36, 72, 108, 144.....
Numbers that can divide 3,4,6,9 leaving remainder 2 = 38, 74, 110, 146........
It is clear that the no. which is divisible by 11, and the no. divided by 3,4,6,9 leaving remainder 2, is the same.
So, answer is 110 ( from multiples of 36 ), because it is the smallest multiple of 11 which can divide 3,4,6,9 leaving remainder 2.
Hope it helps you !!!
LCM = 2 * 2 * 3 * 3 = 36
i.e. 36 can divide 3,4,6,9 completely.
and 38 can divide 3, 4, 6, 9 leaving remainder 2.
Multiples of 36 = 36, 72, 108, 144.....
Numbers that can divide 3,4,6,9 leaving remainder 2 = 38, 74, 110, 146........
It is clear that the no. which is divisible by 11, and the no. divided by 3,4,6,9 leaving remainder 2, is the same.
So, answer is 110 ( from multiples of 36 ), because it is the smallest multiple of 11 which can divide 3,4,6,9 leaving remainder 2.
Hope it helps you !!!
Anonymous:
There may be other method too, but I solved in this way.
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