Math, asked by ts763011, 11 months ago

Find the smallest number which is divisible by 12, 15 and 20
completely​

Answers

Answered by prabhleen2411
1

Step-by-step explanation:

How do we find it? Let’s factor your numbers first.

12 = 2 x 2 x 3

15 = 3 x 5

20 = 2 x 2 x 5

We first find the LCM of 12 and 15. Take each factor. Find the number in which it is repeated the most times and put that in the LCM.

For 2, it is repeated twice in 12. 3 is repeated once in 12 and 15 so we just put 3, and 5 for 12. The LCM of 12 and 15 is 2 x 2 x 3 x 5, or 60.

The LCM of 60 and 20 is just 60.

The answer is 60.

Answered by alwaysjocular
0

Answer:

60

Step-by-step explanation:

60 is divisible by 12, 15 as well as 20

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