Question

Find the smallest number which is divisible by 28and 32 leaving remainder 8 and 12

Answer 1

hye

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aim : to Find the smallest number which is divisible by 28and 32 leaving remainder 8 and 12

so let us detect ,

=>28-8 = 20

=>32 - 12 = 20

so the numbers are 20 and 20

now let us find the hcf of 20 and 20 through prime factoristaion method

it is there in the photo given below

we see that the hcf is 20

∴20 is the  smallest number which is divisible by 28and 32 leaving remainder 8 and 12

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hope it helps u..........