Question

Find the smallest number which is divisible by each of the numbers 6,9and15

Answer 1

Since, we need to find the smallestsquare number divisible by 6, 9 and 15and in above prime factorization of thenumbers we observe that 2 and 5 does not appear in pair, therefore we multiply the L.C.M, 90 by 2 × 5. Hence, The required smallest square number= 90 × 2 × 5 = 900.