Question

find the smallest number which is exactly divisible by 28 36 and 45 on adding 21​

Answer 1

Answer: 10080

1260 x 8 = 10080 which is five digit. Therefore 10080 is the smallest 5 digit number which is exactly divisible by 21, 28, 36, 45.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

LCM of 28 , 36 and 45 will be the smallest number which is divisible by 28,36 and 45

LCM = 1260

smallest number divisible by 28 36 and 45 on adding 21

= 1260-21

= 1239