Question

find the smallest number which is exactly divisible by 30,36,45 if 19 is added to it​

Answer 1

Answer:

first let's find out LCM of 30, 36 and 45

30= 5×2×3

36=3×2×3×2

45=3×3×5

LCM=3×3×2×2×5

LCM=180

now, 180-19= 161 is the answer

if you add 19 to 161 , answer would be 180 which is exactly divisible by 30, 36, 45

hope this helps,

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