Question

find the smallest number which is exactly divisible by 32 and 72​

Answer 1

Given,

The given numbers are 32 and 72.

To find,

The smallest number which is exactly divisible by the given numbers.

Solution,

To solve this mathematical problem, we need to calculate the LCM or Least Common Multiple of the given main numbers. The final result of the LCM will be the necessary smallest number which is divisible by both 32 and 72.

Prime factorization :

32 = 2×2×2×2×2 = 2⁵

72 = 2×2×2×3×3 = 2³×3²

Superset list = 2⁵ and 3²

LCM = 2⁵×3² = 2×2×2×2×2×3×3 = 288

Hence, the smallest number will be 288.

Answer 2

Answer:

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