. Find the smallest number which is on being added 23 to it is exactly divisible by 32,36,48and 96
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Find the smallest number which is on being added 23 to it is exactly divisible by 32,36,48and 96
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265 is the required smallest number which, on being added 23 to it, is exactly divisible by 32, 36, 48 and 96.
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The LCM of 32,36,48 and 96 is 288.So,288 - 23 = 265.Therefore,265 is the smallest number which is on being added to 23 is exactly divisible by 32,36,48 and 96.
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