find the smallest number which is when increased by 19 exaclty divisible by 24,48,96 and 144
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Answer:
The smallest number which when increased by 20 is exactly divisible by 90 and 144 is given as -
First of all let us find a number which is exactly divisible by 90 and 144 like -
90*8=720 and 144*5=720
Now,
To get smallest number which when increased by 20 is exactly divisible by 90 and 144 do
< 720 - 20 = 700 >
so, 700 is the smallest no. which when increased by 20 is exactly divisible by 90 and 144.
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